The Epic Thread of Random-ness [MERGED]

BOLLOCKS!

I am SO fed up with work now, I feel like telling them to stick it. I've done ALL that I can do on this ASP and its not enough, I even had a snotty remark about "stupid little syntax mistakes", well that would be because I don't understand the F*CKING THING!!!!

So now I'm continuing working on it on Monday despite the fact I don't understand any of this garbage code they've written.
 
compbeatlc7.gif
 
Remember School Days, Remember maths :innocent:
I have a Theorem to Prove: 4 = 3

Proof:-

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3
^ Proved! :yes:
 
Remember School Days, Remember maths :innocent:
I have a Theorem to Prove: 4 = 3

Proof:-

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3
^ Proved! :yes:[/b]

:huh: lol
 
Remember School Days, Remember maths :innocent:
I have a Theorem to Prove: 4 = 3

Proof:-

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3
^ Proved! :yes:[/b]
:wacko:
 

OMG :lol:


Remember School Days, Remember maths :innocent:
I have a Theorem to Prove: 4 = 3

Proof:-

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3
^ Proved! :yes:[/b]

:rolleyes: what on earth :lol: am i at Uni :lol: in maths lesson
 
Remember School Days, Remember maths :innocent:
I have a Theorem to Prove: 4 = 3

Proof:-

Suppose:
a + b = c

This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:
4 = 3
^ Proved! :yes:[/b]
:rollin:

:wub: Ahhh Math.
 
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